COSMO · STUDY + TEACHING DECKNumber Theory
October 22, 2025
C. A question worth sharingChinese Remainder Theorem
Reconstruct one number from compatible remainder clues.
ThinkCompareExplain
Today’s routeA question becomes an explanation.
Try
Enter through a problem. A partial attempt counts.
Connect
Use residue, coprime, simultaneous congruence to name what you notice.
Convince
Build an argument a partner can check.
The goal is a method someone else can use.
The openerStart with a question.
Opening problem
Find the smallest positive n with n = 2 mod 3 and n = 3 mod 5.
Think · 2 min
Sketch, test a small case, or make a first guess.
Pair · 3 min
Compare methods. Find one thing you agree on and one question.
Be ready to share your route, even if it is unfinished.
Compare before checkingPut two attempts in conversation.
Explain
Tell a partner how you started. Let them finish before responding.
Question
Which step feels certain? Which step still needs evidence?
Build
Combine one useful idea from each attempt into a new route.
Can you explain your partner’s method in your own words?
Board conversationNotice before naming.
Look for structure
- 01Try a small case and record every step.
- 02Separate what changes from what stays fixed.
- 03State the pattern in a sentence before naming the theorem.
Make a conjecture
We think ___ because ___. A case that might break this is ___.
What changed? What stayed the same?
Useful languageNow the language has a job.
simultaneous congruence
several remainder conditions at once
Use one of these words to explain something you already noticed.
The core ideaKeep the idea. Explain the conditions.
x≡a(modm),x≡b(modn),gcd(m,n)=1⟹x unique mod mn The idea
Reconstruct one number from compatible remainder clues.
What to remember
Several small clocks can identify one position on a much larger clock.
What information does this method keep?
Worked exampleOne route, one decision at a time
The problem
Solve x = 1 mod 4 and x = 2 mod 5.
Predict each next step
- 01Write x = 1 + 4k.
- 02Then 1 + 4k = 2 mod 5.
- 03So 4k = 1 mod 5 and k = 4 mod 5.
- 04Thus x = 17 mod 20.
Which step needs a reason, not just a calculation?
See the structureThe structure behind chinese remainder theorem
Read the representation
Reconstruct one number from compatible remainder clues.
Look together
Point to the part that explains the relationship. Change one input and predict what changes.
What can you see here that was harder to see in words?
Two approachesCompare the reasoning.
Structural method
- 01Name the objects and conditions.
- 02Use a reusable relationship.
- 03Explain why the method must work.
Brute force
- 01May help with a small test case.
- 02Can hide the general reason.
- 03Becomes unreliable when the scale grows.
Which route can you justify? What would you test first?
Reasoning clinicFind the step that needs repair.
Investigate these concerns
- 01May help with a small test case.
- 02Can hide the general reason.
- 03Becomes unreliable when the scale grows.
Repair together
Name the missing condition. Try a small counterexample. Rewrite one step so it is justified.
A useful correction explains why the original step fails.
Work togetherInvestigate chinese remainder theorem
Your shared task
Teams encode secret numbers as remainder clues and trade clues with another team for reconstruction.
Explore
4 min - test cases
Compare
5 min - form a rule
Defend
4 min - defend the rule
Everyone should be able to explain the group’s final claim.
Share → connectWhat did the room discover?
Bring your evidence
Share a conjecture, a useful example, or a route that changed.
Connections to investigate
- 01Several small clocks can identify one position on a much larger clock.
- 02A complete solution names the condition that makes the method valid.
- 03A counterexample is useful when it exposes a missing condition.
Which observation explains the mechanism?
Try → explain → checkYour turn to build the route
The problem
Solve x = 2 mod 3, x = 3 mod 4, x = 1 mod 5.
Predict each next step
- 01Combine the first two to get x = 11 mod 12.
- 02Write x = 11 + 12k.
- 03Then k = 0 mod 5.
- 04So x = 11 mod 60.
Which step needs a reason, not just a calculation?
Convince a skepticTurn a pattern into a proof.
The claim
Pairwise coprime moduli determine one residue class modulo their product.
Build the argument
- 01Each modulus has an inverse modulo every other modulus.
- 02Build a term that is 1 for one modulus and 0 for the others.
- 03Add the terms; uniqueness follows because any two solutions differ by every modulus.
What does each step rely on? Where are the conditions used?
Stretch togetherTake the idea somewhere new.
Transfer challenge
A number leaves remainders 4, 2, and 1 when divided by 5, 7, and 8. Find the least positive value.
Choose a route
Name the objects, the conditions, and a relationship that might help. Start with one test case.
What transfers from the earlier example? What is different?
Peer reviewCheck the argument together.
Restate
Explain the other person’s route before evaluating it.
Test
Try a small case or boundary case. Does every step still make sense?
Revise
Fix an assumption, add a reason, or find a second method.
Where did your thinking change?
Beyond this problemWhere might this idea help?
A connection
Remainder reconstruction appears in calendars, distributed computation, and modular data storage.
Discuss the model
- 01What objects or quantities are represented?
- 02Which relationship from today is preserved?
- 03What assumption would you check before trusting it?
Invent one more situation with the same structure.
Exit ticketLeave with an explanation.
Question 1
Find the smallest positive n with n = 2 mod 3 and n = 3 mod 5.
Question 2
Explain why this claim is true: Pairwise coprime moduli determine one residue class modulo their product.
Question 3
A number leaves remainders 4, 2, and 1 when divided by 5, 7, and 8. Find the least positive value.
Choose one. Write an answer with a reason, then compare with a partner.
Reflect togetherMake your thinking visible.
I used to think…
Name a claim or approach that changed.
Now I can explain…
Give the reason, not only the result.
I still wonder…
Write a question worth bringing to the next circle.
Share one sentence. Ask one follow-up question.
The idea to keepSeveral small clocks can identify one position on a much larger clock.
Use the matching practice sets to move from direct examples to proof and transfer.
A good question belongs to everyone in the room. 1 / 21
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